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Take out the constant $8$ from the integral
Learn how to solve integrals by partial fraction expansion problems step by step online.
$8\int\frac{x}{x^3+x^2-x-1}dx$
Learn how to solve integrals by partial fraction expansion problems step by step online. Find the integral int((8x)/(x^3+x^2-x+-1))dx. Take out the constant 8 from the integral. We can factor the polynomial x^3+x^2-x-1 using the rational root theorem, which guarantees that for a polynomial of the form a_nx^n+a_{n-1}x^{n-1}+\dots+a_0 there is a rational root of the form \pm\frac{p}{q}, where p belongs to the divisors of the constant term a_0, and q belongs to the divisors of the leading coefficient a_n. List all divisors p of the constant term a_0, which equals -1. Next, list all divisors of the leading coefficient a_n, which equals 1. The possible roots \pm\frac{p}{q} of the polynomial x^3+x^2-x-1 will then be.