Final Answer
$\frac{2x-7}{2\left(-\frac{17}{16}+\left(x-\frac{5}{4}\right)^2\right)}$
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Step-by-step Solution
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1
Use the complete the square method to factor the trinomial of the form $ax^2+bx+c$. Take common factor $a$ ($2$) to all terms
$\frac{2x-7}{2\left(x^2-\frac{5}{2}x+\frac{1}{2}\right)}$
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$\frac{2x-7}{2\left(x^2-\frac{5}{2}x+\frac{1}{2}\right)}$
Learn how to solve polynomial factorization problems step by step online. Factor by completing the square (2x-7)/(2x^2-5x+1). Use the complete the square method to factor the trinomial of the form ax^2+bx+c. Take common factor a (2) to all terms. Add and subtract \displaystyle\left(\frac{b}{2a}\right)^2. Factor the perfect square trinomial x^2+-\frac{5}{2}xx+\frac{25}{16}. Subtract the values \frac{1}{2} and -\frac{25}{16}.
Final Answer
$\frac{2x-7}{2\left(-\frac{17}{16}+\left(x-\frac{5}{4}\right)^2\right)}$