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Find the break even points of the polynomial $\frac{2x-7}{2x^2-5x+1}$ by putting it in the form of an equation and then set it equal to zero
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$\frac{2x-7}{2x^2-5x+1}=0$
Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression (2x-7)/(2x^2-5x+1). Find the break even points of the polynomial \frac{2x-7}{2x^2-5x+1} by putting it in the form of an equation and then set it equal to zero. Multiply both sides of the equation by 2x^2-5x+1. We need to isolate the dependent variable , we can do that by simultaneously subtracting -7 from both sides of the equation. Canceling terms on both sides.