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$\frac{\frac{3}{\left(x^3-9\right)\left(x^3+2x^2-3x\right)}}{x^2-3x}=0$
Learn how to solve equations problems step by step online. Solve the equation (3/((x^3-9)(x^3+2x^2-3x)))/(x^2-3x)$=0$. Resolver la ecuaci贸n para x. Divide fractions \frac{\frac{3}{\left(x^3-9\right)\left(x^3+2x^2-3x\right)}}{x^2-3x} with Keep, Change, Flip: \frac{a}{b}\div c=\frac{a}{b}\div\frac{c}{1}=\frac{a}{b}\times\frac{1}{c}=\frac{a}{b\cdot c}. No solutions exist for this equation.