Final answer to the problem
$\frac{y^{\prime}}{y}=\frac{1}{2x^3+7x^2y-4xy^2}\left(6x^{2}+7\left(2xy+x^2y^{\prime}\right)-4\left(y^2+2xy\cdot y^{\prime}\right)\right)$
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Step-by-step Solution
How should I solve this problem?
- Find the derivative using logarithmic differentiation
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Prove from LHS (left-hand side)
- Load more...
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Simplifying
$\frac{d}{dx}\left(2x^3+7x^2y-4xy^2\right)$
Learn how to solve differential calculus problems step by step online.
$\frac{d}{dx}\left(2x^3+7x^2y-4xy^2\right)$
Learn how to solve differential calculus problems step by step online. Factor the expression 2x^3+7x^2y1*-4xy^2. Simplifying. To derive the function 2x^3+7x^2y-4xy^2, use the method of logarithmic differentiation. First, assign the function to y, then take the natural logarithm of both sides of the equation. Apply natural logarithm to both sides of the equality. Apply logarithm properties to both sides of the equality.
Final answer to the problem
$\frac{y^{\prime}}{y}=\frac{1}{2x^3+7x^2y-4xy^2}\left(6x^{2}+7\left(2xy+x^2y^{\prime}\right)-4\left(y^2+2xy\cdot y^{\prime}\right)\right)$
