$\left(3a^2b^4-\frac{1}{2}m^6\right).\:\left(3a^2b^4+\frac{1}{2}m^6\right)$
$150\cdot\frac{3}{1}$
$5x-4x-2x+x$
$-a-\frac{1}{b^9}$
$3x^2=0$
$4.2-3.25$
$\left(3x+1\right)\left(2a+3\right)+2$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!