Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Find break even points
- Solve for x
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
- Load more...
Find the break even points of the polynomial $\left(2x+3\right)^2-\left(2x-3\right)^2+\left(3x-4\right)^2-8x^2-16$ by putting it in the form of an equation and then set it equal to zero
Learn how to solve limits to infinity problems step by step online.
$\left(2x+3\right)^2-\left(2x-3\right)^2+\left(3x-4\right)^2-8x^2-16=0$
Learn how to solve limits to infinity problems step by step online. Find the break even points of the expression (2x+3)^2-(2x-3)^2(3x-4)^2-8x^2+-16. Find the break even points of the polynomial \left(2x+3\right)^2-\left(2x-3\right)^2+\left(3x-4\right)^2-8x^2-16 by putting it in the form of an equation and then set it equal to zero. A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. The power of a product is equal to the product of it's factors raised to the same power. Simplify the product -(4x^2-12x+9).