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# Find the limit of $\left(1+\frac{-1}{x}\right)^x$ as $x$ approaches $\infty$

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##  Final Answer

$\frac{1}{e}$
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##  Step-by-step Solution 

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Rewrite the limit using the identity: $a^x=e^{x\ln\left(a\right)}$

$\lim_{x\to\infty }\left(e^{x\ln\left(1+\frac{-1}{x}\right)}\right)$

Learn how to solve problems step by step online.

$\lim_{x\to\infty }\left(e^{x\ln\left(1+\frac{-1}{x}\right)}\right)$

Learn how to solve problems step by step online. Find the limit of (1+-1/x)^x as x approaches infinity. Rewrite the limit using the identity: a^x=e^{x\ln\left(a\right)}. Apply the power rule of limits: \displaystyle{\lim_{x\to a}f(x)^{g(x)} = \lim_{x\to a}f(x)^{\displaystyle\lim_{x\to a}g(x)}}. The limit of a constant is just the constant. Rewrite the product inside the limit as a fraction.

##  Final Answer

$\frac{1}{e}$

##  Exact Numeric Answer

$0.367879$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Limits by Direct SubstitutionLimits by L'Hôpital's ruleLimits by factoringLimits by rationalizing

SnapXam A2

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1
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3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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