$\int_0^2x\left(4x^2+3x\right)dx$
$2\left(x\:+\:4\right)\:+\:5x\:-\:3\:$
$\ln\frac{3}{x}\:=2$
$2a^2+a$
$3x-8\ge x+6$
$\left(5r-3t\right)\left(-3t+5r\right)$
$x'=e^{t+x}$
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