Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Solve by completing the square
- Solve for x
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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Factor the trinomial $\left(2x^2+5x-7\right)$ of the form $ax^2+bx+c$, first, make the product of $2$ and $-7$
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$\left(2\right)\left(-7\right)=-14$
Learn how to solve exponential equations problems step by step online. Solve the exponential equation e^x(2x^2+5x+-7)=0. Factor the trinomial \left(2x^2+5x-7\right) of the form ax^2+bx+c, first, make the product of 2 and -7. Now, find two numbers that multiplied give us -14 and add up to 5. Rewrite the original expression. Factor \left(2x^2+7x-2x-7\right) by the greatest common divisor 2.