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Exercise

$2^{6x+7}=\left(\frac{1}{8}\right)^{1-5x}$

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Final answer to the exercise

$x=\frac{\log_{2}\left(\frac{1}{8}\right)-7}{6+5\log_{2}\left(\frac{1}{8}\right)}$

Exact Numeric Answer

$x=1.1111111$

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