Solve the exponential equation $4^x=\frac{1}{16}$

Step-by-step Solution

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Final answer to the problem

$x=\frac{\log_{2}\left(\frac{1}{16}\right)}{2}$
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Step-by-step Solution

How should I solve this problem?

  • Solve for x
  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
  • Simplify
  • Find the integral
  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find the roots
  • Find break even points
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Decompose $4$ in it's prime factors

$\left(2^{2}\right)^x=\frac{1}{16}$

Learn how to solve exponential equations problems step by step online.

$\left(2^{2}\right)^x=\frac{1}{16}$

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Learn how to solve exponential equations problems step by step online. Solve the exponential equation 4^x=1/16. Decompose 4 in it's prime factors. Simplify \left(2^{2}\right)^x using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 2 and n equals x. We can take out the unknown from the exponent by applying logarithms in base 10 to both sides of the equation. Use the following rule for logarithms: \log_b(b^k)=k.

Final answer to the problem

$x=\frac{\log_{2}\left(\frac{1}{16}\right)}{2}$

Exact Numeric Answer

$x=-2$

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Function Plot

Plotting: $4^x-\frac{1}{16}$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Exponential Equations

Exponential equations are those where the unknown appears only in the exponents of powers of constant bases.

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