Solve the quadratic equation $r^1+r^2=\frac{5}{6}$

Step-by-step Solution

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Final answer to the problem

$r=-\frac{1}{2}+\sqrt{\frac{5}{6}+\frac{1}{4}},\:r=-\frac{1}{2}-\sqrt{\frac{5}{6}+\frac{1}{4}}$
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Step-by-step Solution

How should I solve this problem?

  • Factor
  • Solve for r
  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
  • Simplify
  • Find the integral
  • Find the derivative
  • Factor by completing the square
  • Find the roots
  • Find break even points
  • Load more...
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Any expression to the power of $1$ is equal to that same expression

$r+r^2=\frac{5}{6}$

Learn how to solve differential calculus problems step by step online.

$r+r^2=\frac{5}{6}$

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Learn how to solve differential calculus problems step by step online. Solve the quadratic equation r^1+r^2=5/6. Any expression to the power of 1 is equal to that same expression. Factor the polynomial r+r^2. Add and subtract \left(\frac{b}{2}\right)^2, where in this case b equals 1. Now we can factor r^2+x+\frac{1}{4} as a squared binomial of the form \left(x+\frac{b}{2}\right)^2. Calculate the power \sqrt{\frac{1}{4}}.

Final answer to the problem

$r=-\frac{1}{2}+\sqrt{\frac{5}{6}+\frac{1}{4}},\:r=-\frac{1}{2}-\sqrt{\frac{5}{6}+\frac{1}{4}}$

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Function Plot

Plotting: $r^1+r^2-\frac{5}{6}$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

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