Find the integral $\int\frac{2y^3+3}{9x+5}dx$

Step-by-step Solution

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Final answer to the problem

$\frac{1}{9}\left(2y^3+3\right)\ln\left|9x+5\right|+C_0$
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Step-by-step Solution

How should I solve this problem?

  • Integrate using basic integrals
  • Integrate by partial fractions
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
  • Integrate by trigonometric substitution
  • Weierstrass Substitution
  • Integrate using trigonometric identities
  • Product of Binomials with Common Term
  • FOIL Method
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The integral of a function times a constant ($2y^3+3$) is equal to the constant times the integral of the function

$\left(2y^3+3\right)\int\frac{1}{9x+5}dx$

Learn how to solve integrals of rational functions problems step by step online.

$\left(2y^3+3\right)\int\frac{1}{9x+5}dx$

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Learn how to solve integrals of rational functions problems step by step online. Find the integral int((2y^3+3)/(9x+5))dx. The integral of a function times a constant (2y^3+3) is equal to the constant times the integral of the function. Apply the formula: \int\frac{n}{ax+b}dx=\frac{n}{a}\ln\left(ax+b\right)+C, where a=9, b=5 and n=1. As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration C.

Final answer to the problem

$\frac{1}{9}\left(2y^3+3\right)\ln\left|9x+5\right|+C_0$

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Function Plot

Plotting: $\frac{1}{9}\left(2y^3+3\right)\ln\left(9x+5\right)+C_0$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Integrals of Rational Functions

Integrals of rational functions of the form R(x) = P(x)/Q(x).

Used Formulas

See formulas (1)

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