$\frac{4x^3-x}{2x+3}$

$16x^2+8x+1=0$

$\left(2x-5\right)\left(x+2\right)$

$\lim_{x\to\infty}\left(\frac{8-\sqrt{x}}{1+4\sqrt{x}}\right)$

$\frac{x^{3}y^{5}z^{8}}{4x^{2}y^{6}z^{11}}$

$\int\frac{3x^2-3x+13}{\left(x+3\right)\left(x-1\right)}dx$

$\lim_{x\to\infty}\:\left(\frac{8}{9}\right)^x+1$