Find the implicit derivative $\frac{d}{dx}\left(x^xy=\sqrt[3]{\frac{x\left(x+1\right)\left(x-2\right)}{\left(x^2+1\right)\left(2x+3\right)}}\right)$

Step-by-step Solution

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Final answer to the problem

$\left(\ln\left(x\right)+1\right)x^xy+x^xy^{\prime}=\frac{\left(\left(x+1\right)\left(x-2\right)+x\left(x-2+x+1\right)\right)\left(x^2+1\right)\left(2x+3\right)+\left(-x-1\right)x\left(x-2\right)\left(2x\left(2x+3\right)+2\left(x^2+1\right)\right)}{3\left(x^2+1\right)^2\left(2x+3\right)^2}\sqrt[3]{\left(\frac{\left(x^2+1\right)\left(2x+3\right)}{x\left(x+1\right)\left(x-2\right)}\right)^{2}}$
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Step-by-step Solution

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  • Find the derivative using the definition
  • Find the derivative using the product rule
  • Find the derivative using the quotient rule
  • Find the derivative using logarithmic differentiation
  • Find the derivative
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
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Apply implicit differentiation by taking the derivative of both sides of the equation with respect to the differentiation variable

$\frac{d}{dx}\left(x^xy\right)=\frac{d}{dx}\left(\sqrt[3]{\frac{x\left(x+1\right)\left(x-2\right)}{\left(x^2+1\right)\left(2x+3\right)}}\right)$

Learn how to solve integrals of rational functions problems step by step online.

$\frac{d}{dx}\left(x^xy\right)=\frac{d}{dx}\left(\sqrt[3]{\frac{x\left(x+1\right)\left(x-2\right)}{\left(x^2+1\right)\left(2x+3\right)}}\right)$

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Learn how to solve integrals of rational functions problems step by step online. Find the implicit derivative d/dx(x^xy=((x(x+1)(x-2))/((x^2+1)(2x+3)))^(1/3)). Apply implicit differentiation by taking the derivative of both sides of the equation with respect to the differentiation variable. Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g', where f=x^x and g=y. The derivative of the linear function is equal to 1. The power rule for differentiation states that if n is a real number and f(x) = x^n, then f'(x) = nx^{n-1}.

Final answer to the problem

$\left(\ln\left(x\right)+1\right)x^xy+x^xy^{\prime}=\frac{\left(\left(x+1\right)\left(x-2\right)+x\left(x-2+x+1\right)\right)\left(x^2+1\right)\left(2x+3\right)+\left(-x-1\right)x\left(x-2\right)\left(2x\left(2x+3\right)+2\left(x^2+1\right)\right)}{3\left(x^2+1\right)^2\left(2x+3\right)^2}\sqrt[3]{\left(\frac{\left(x^2+1\right)\left(2x+3\right)}{x\left(x+1\right)\left(x-2\right)}\right)^{2}}$

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Function Plot

Plotting: $\left(\ln\left(x\right)+1\right)x^xy+x^xy^{\prime}=\frac{\left(\left(x+1\right)\left(x-2\right)+x\left(x-2+x+1\right)\right)\left(x^2+1\right)\left(2x+3\right)+\left(-x-1\right)x\left(x-2\right)\left(2x\left(2x+3\right)+2\left(x^2+1\right)\right)}{3\left(x^2+1\right)^2\left(2x+3\right)^2}\sqrt[3]{\left(\frac{\left(x^2+1\right)\left(2x+3\right)}{x\left(x+1\right)\left(x-2\right)}\right)^{2}}$

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0
a
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f
g
m
n
u
v
w
x
y
z
.
(◻)
+
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×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Integrals of Rational Functions

Integrals of rational functions of the form R(x) = P(x)/Q(x).

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