Final Answer
$\frac{1}{-x}+x+C_0$
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Step-by-step Solution
Problem to solve:
$\int\frac{1+x^2}{x^2}dx$
Specify the solving method
1
Expand the fraction $\frac{1+x^2}{x^2}$ into $2$ simpler fractions with common denominator $x^2$
$\int\left(\frac{1}{x^2}+\frac{x^2}{x^2}\right)dx$
Learn how to solve differential calculus problems step by step online.
$\int\left(\frac{1}{x^2}+\frac{x^2}{x^2}\right)dx$
Learn how to solve differential calculus problems step by step online. Find the integral int((1+x^2)/(x^2))dx. Expand the fraction \frac{1+x^2}{x^2} into 2 simpler fractions with common denominator x^2. Simplify the resulting fractions. Expand the integral \int\left(\frac{1}{x^2}+1\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{1}{x^2}dx results in: \frac{1}{-x}.
Final Answer
$\frac{1}{-x}+x+C_0$