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Integrate the function $\frac{1}{1-\sin\left(o\right)}$ from 0 to $1$

Step-by-step Solution

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asin
acos
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sinh
cosh
tanh
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sech
csch

asinh
acosh
atanh
acoth
asech
acsch
Solving: $\int_{0}^{1}\frac{1}{1-\sin\left(o\right)}do$

Final Answer

$2.408219$
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Step-by-step Solution

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We can solve the integral $\int\frac{1}{1-\sin\left(o\right)}do$ by applying the method Weierstrass substitution (also known as tangent half-angle substitution) which converts an integral of trigonometric functions into a rational function of $t$ by setting the substitution

$t=\tan\left(\frac{o}{2}\right)$

Learn how to solve definite integrals problems step by step online.

$t=\tan\left(\frac{o}{2}\right)$

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Learn how to solve definite integrals problems step by step online. Integrate the function 1/(1-sin(o)) from 0 to 1. We can solve the integral \int\frac{1}{1-\sin\left(o\right)}do by applying the method Weierstrass substitution (also known as tangent half-angle substitution) which converts an integral of trigonometric functions into a rational function of t by setting the substitution. Hence. Substituting in the original integral we get. Simplifying.

Final Answer

$2.408219$

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Function Plot

Plotting: $\frac{1}{1-\sin\left(o\right)}$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

Used Formulas

2. See formulas

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