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$de\:3x^2y,restar\:-8x^2y$
$2^{18}$
$5x+3=-27$
$-7+5-8-9+8-11-15+13-16$
$\frac{2}{sin^2x}=\frac{1}{1-cosx}+\frac{1}{1+cosx}$
$\left(\frac{5m^{12}n^3}{4m^{15}n^4}\right)^2$
$\frac{\left(y^{-23}\right)\left(y^{99}\right)}{\left(y^{-97}\right)\left(y^{-18}\right)}$
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