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Factor the trinomial $3x^2+1x-10$ of the form $ax^2+bx+c$, first, make the product of $3$ and $-10$
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$\left(3\right)\left(-10\right)=-30$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 3x^2+x+-10=0. Factor the trinomial 3x^2+1x-10 of the form ax^2+bx+c, first, make the product of 3 and -10. Now, find two numbers that multiplied give us -30 and add up to 1. Rewrite the original expression. Factor 3x^2+6x-5x-10 by the greatest common divisor 3.