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- Integrate by partial fractions
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Factor the polynomial $9580x+x^2$. Add and subtract $\left(\frac{b}{2}\right)^2$, replacing $b$ by it's value $9580$
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$x^2+9580x+22944100-22944100\leq 26500$
Learn how to solve inequalities problems step by step online. Solve the inequality 9580x+x^2<=26500. Factor the polynomial 9580x+x^2. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value 9580. Now, we can factor x^2+9580x+22944100 as a squared binomial of the form \left(x+\frac{b}{2}\right)^2. Moving the term -22944100 to the other side of the inequation with opposite sign. Add the values 26500 and 22944100.