$\frac{x+3}{\left(4\cdot x^2\right)+8}$

$\left(y^{-4}\right)^{-2}$

$\lim_{x\to2}\sqrt{2x^2+4}$

$\frac{dy}{dx}=x\cos^2y$

$\frac{1}{\tan\left(x\right)}+\frac{\sin\left(x\right)}{1+\cos\left(x\right)}=\frac{1}{\sin\left(x\right)}$

$216x^1y^1z^1-343m^1w^{1a}$

$25z^2+30z+16$