$u^2-16$
$16+8\left(2x+3z^6\right)+\left(2x+3z^6\right)^2$
$8\left(3b+2\right)+7\left(3b+2\right)$
$\int\left(\frac{4x}{\left(x-6\right)}\right)dx$
$\lim_{x\to2}\left(\left(x^2-4\right)\left(\left|-2x\right|\right)\right)$
$3x^2+14x+18$
$\frac{x^3+x^2-x-3}{x^2-3}$
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