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Rewrite the fraction $\frac{5x^2+6x-8}{\left(x-6\right)\left(x-2\right)^4\left(x+1\right)^3}$ in $8$ simpler fractions using partial fraction decomposition
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$\frac{5x^2+6x-8}{\left(x-6\right)\left(x-2\right)^4\left(x+1\right)^3}=\frac{A}{x-6}+\frac{B}{\left(x-2\right)^4}+\frac{C}{\left(x+1\right)^3}+\frac{D}{x-2}+\frac{F}{\left(x-2\right)^{2}}+\frac{G}{\left(x-2\right)^{3}}+\frac{H}{x+1}+\frac{I}{\left(x+1\right)^{2}}$
Learn how to solve differential calculus problems step by step online. Find the integral int((5x^2+6x+-8)/((x-6)(x-2)^4(x+1)^3))dx. Rewrite the fraction \frac{5x^2+6x-8}{\left(x-6\right)\left(x-2\right)^4\left(x+1\right)^3} in 8 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C, D, F, G, H, I. The first step is to multiply both sides of the equation from the previous step by \left(x-6\right)\left(x-2\right)^4\left(x+1\right)^3. Multiplying polynomials. Simplifying.