Solved example of first order differential equations
Take $\frac{5}{4}$ out of the fraction
Rewrite the differential equation in the standard form $M(x,y)dx+N(x,y)dy=0$
The differential equation $ydy-\frac{5}{4}x^2dx=0$ is exact, since it is written in the standard form $M(x,y)dx+N(x,y)dy=0$, where $M(x,y)$ and $N(x,y)$ are the partial derivatives of a two-variable function $f(x,y)$ and they satisfy the test for exactness: $\displaystyle\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$. In other words, their second partial derivatives are equal. The general solution of the differential equation is of the form $f(x,y)=C$
Find the derivative of $M(x,y)$ with respect to $y$
The derivative of the constant function ($-\frac{5}{4}x^2$) is equal to zero
Find the derivative of $N(x,y)$ with respect to $x$
The derivative of the constant function ($y$) is equal to zero
Using the test for exactness, we check that the differential equation is exact
The integral of a constant by a function is equal to the constant multiplied by the integral of the function
Apply the power rule for integration, $\displaystyle\int x^n dx=\frac{x^{n+1}}{n+1}$, where $n$ represents a number or constant function, such as $2$
Since $y$ is treated as a constant, we add a function of $y$ as constant of integration
Integrate $M(x,y)$ with respect to $x$ to get
The derivative of the constant function ($-\frac{5}{12}x^{3}$) is equal to zero
The derivative of $g(y)$ is $g'(y)$
Now take the partial derivative of $-\frac{5}{12}x^{3}$ with respect to $y$ to get
Simplify and isolate $g'(y)$
$x+0=x$, where $x$ is any expression
Rearrange the equation
Set $y$ and $0+g'(y)$ equal to each other and isolate $g'(y)$
Integrate both sides with respect to $y$
Applying the power rule for integration, $\displaystyle\int x^n dx=\frac{x^{n+1}}{n+1}$, where $n$ represents a number or constant function, in this case $n=1$
Find $g(y)$ integrating both sides
We have found our $f(x,y)$ and it equals
Then, the solution to the differential equation is
We need to isolate the dependent variable $y$, we can do that by subtracting $-\frac{5}{12}x^{3}$ from both sides of the equation
Eliminate the $\frac{1}{2}$ from the left, multiplying both sides of the equation by the inverse of $\frac{1}{2}$
Removing the variable's exponent
As in the equation we have the sign $\pm$, this produces two identical equations that differ in the sign of the term $\sqrt{2\left(C_0+\frac{5}{12}x^{3}\right)}$. We write and solve both equations, one taking the positive sign, and the other taking the negative sign
Multiply the single term $2$ by each term of the polynomial $\left(C_0+\frac{5}{12}x^{3}\right)$
We can rename $2C_0$ as other constant
Multiply the single term $2$ by each term of the polynomial $\left(C_0+\frac{5}{12}x^{3}\right)$
Find the explicit solution to the differential equation
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