👉 Try now
NerdPal
! Our new math app on
iOS
and
Android
Calculators
Topics
Solving Methods
Step Checker
Book solutions
Algebra Baldor
Go Premium
Topics
Login
English
Español
Português
Tap to take a pic of the problem
Binomial Conjugates Calculator
Get detailed solutions to your math problems with our
Binomial Conjugates step-by-step calculator
. Practice your math skills and learn step by step with our math solver.
Check out all of our online calculators here
.
Go!
Math mode
Text mode
Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻
2
◻
◻
√
◻
√
◻
√
◻
◻
√
∞
e
π
ln
log
log
◻
lim
d/dx
D
□
x
∫
∫
◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc
asin
acos
atan
acot
asec
acsc
sinh
cosh
tanh
coth
sech
csch
asinh
acosh
atanh
acoth
asech
acsch
Example
Solved Problems
Difficult Problems
$\frac{\cos\left(x\right)}{1-sinx}=secx+tanx$
$\sec+\tan=\frac{\cos}{1-\sin}$
$\frac{sec\:x-1}{tan\:x}=\frac{tan\:x}{sec\:x\:+1}$
$\left(cscy-1\right)\left(cscy+1\right)=ctg^2y$
$\left(csc\left(a\right)-cot\left(a\right)\right)\left(csc\left(a\right)+cot\left(a\right)\right)=1$
$\left(1+cos\right)\left(1-cos\right)=sen^2$
$\frac{1}{sec\left(x\right)+tan\left(x\right)}=\sec\left(x\right)-\tan\left(x\right)$
Struggling with math?
Access detailed step by step solutions to thousands of problems, growing every day!
Join now
Popular problems
$\frac{1-\sin\left(x\right)}{\cos\left(x\right)}=\frac{\cos\left(x\right)}{1+\sin\left(x\right)}$
263 views
$\frac{1-\cos\left(x\right)}{\sin\left(x\right)}=\frac{\sin\left(x\right)}{1+\cos\left(x\right)}$
171 views
$\frac{\cos\left(x\right)}{1+\sin\left(x\right)}=\sec\left(x\right)-\tan\left(x\right)$
168 views
$\frac{\cos\left(x\right)}{1-\sin\left(x\right)}=\sec\left(x\right)+\tan\left(x\right)$
99 views
$\frac{\cos\left(x\right)}{1-\sin\left(x\right)}=\frac{1+\sin\left(x\right)}{\cos\left(x\right)}$
98 views
$\sec\left(x\right)+\tan\left(x\right)=\frac{\cos\left(x\right)}{1-\sin\left(x\right)}$
95 views
$\frac{\sin\left(x\right)}{1-\cos\left(x\right)}=\csc\left(x\right)+\cot\left(x\right)$
92 views
$\frac{cosx}{1+sinx}=secx-tanx$
72 views