Solved example of binomial conjugates
The first term ($a$) is $2$.
The second term ($b$) is $\sqrt{y}$.
Solve the product of difference of squares $\left(2+\sqrt{y}\right)\left(2-\sqrt{y}\right)$
Simplify $\left(\sqrt{y}\right)^2$ using the power of a power property: $\left(a^m\right)^n=a^{m\cdot n}$. In the expression, $m$ equals $\frac{1}{2}$ and $n$ equals $2$
Solve the product of difference of squares $\left(2+\sqrt{y}\right)\left(2-\sqrt{y}\right)$
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