ðŸ‘‰ Try now NerdPal! Our new math app on iOS and Android

# Binomial Conjugates Calculator

## Get detailed solutions to your math problems with our Binomial Conjugates step-by-step calculator. Practice your math skills and learn step by step with our math solver. Check out all of our online calculators here.

Go!
Symbolic mode
Text mode
Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Difficult Problems

1

Here, we show you a step-by-step solved example of binomial conjugates. This solution was automatically generated by our smart calculator:

$\left(2+\sqrt{y}\right)\left(2-\sqrt{y}\right)$

The first term ($a$) is $2$.

The second term ($b$) is $\sqrt{y}$.

Solve the product of difference of squares $\left(2+\sqrt{y}\right)\left(2-\sqrt{y}\right)$

$2^2-\left(\sqrt{y}\right)^2$

Simplify $\left(\sqrt{y}\right)^2$ using the power of a power property: $\left(a^m\right)^n=a^{m\cdot n}$. In the expression, $m$ equals $\frac{1}{2}$ and $n$ equals $2$

$2^2-y$
2

Solve the product of difference of squares $\left(2+\sqrt{y}\right)\left(2-\sqrt{y}\right)$

$4-y$

##  Final answer to the problem

$4-y$

### Are you struggling with math?

Access detailed step by step solutions to thousands of problems, growing every day!