Final answer to the problem
$\frac{y^{\prime}}{y}=\frac{1}{x^3-6x^2-5x+28yx^3-5}\left(3x^{2}-12x-5+28\left(y^{\prime}x^3+3yx^{2}\right)\right)$
Step-by-step Solution
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Math interpretation of the question
$2x^3-2x^2+4x-x^3+3x^2-5x+7\cdot 4yx^3-7x^2-4x-5$
Learn how to solve definition of derivative problems step by step online.
$2x^3-2x^2+4x-x^3+3x^2-5x+7\cdot 4yx^3-7x^2-4x-5$
Learn how to solve definition of derivative problems step by step online. 2 x^3 - 2 x^2 + 4x - 1; x^3 + 3 x^2- 5x + 7 y 4 x^3 - 7 x^2 - 4x - 5 . Math interpretation of the question. Simplifying. Simplify the derivative by applying the properties of logarithms. To derive the function x^3-6x^2-5x+28yx^3-5, use the method of logarithmic differentiation. First, assign the function to y, then take the natural logarithm of both sides of the equation.
Final answer to the problem
$\frac{y^{\prime}}{y}=\frac{1}{x^3-6x^2-5x+28yx^3-5}\left(3x^{2}-12x-5+28\left(y^{\prime}x^3+3yx^{2}\right)\right)$