Final Answer
$c=\frac{1}{\sqrt[3]{b}\sqrt[3]{x}\sqrt[3]{\cos\left(x\right)^{2}}}$
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Step-by-step Solution
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1
When multiplying exponents with same base you can add the exponents: $bc\cdot c^2x\sin\left(x\right)^2\cot\left(x\right)^2$
$c^{3}bx\sin\left(x\right)^2\cot\left(x\right)^2=1$
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$c^{3}bx\sin\left(x\right)^2\cot\left(x\right)^2=1$
Learn how to solve problems step by step online. Solve the equation sin(x)^2bcc^2xcot(x)^2=1. When multiplying exponents with same base you can add the exponents: bc\cdot c^2x\sin\left(x\right)^2\cot\left(x\right)^2. Use trig identities to simplify c^{3}bx\sin\left(x\right)^2\cot\left(x\right)^2 in terms of \cos. Divide both sides of the equation by \cos\left(x\right)^2. Divide both sides of the equation by bx.
Final Answer
$c=\frac{1}{\sqrt[3]{b}\sqrt[3]{x}\sqrt[3]{\cos\left(x\right)^{2}}}$