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$\int\left(\left(x-3\right)^2+3\right)dx$
Learn how to solve integral calculus problems step by step online. Find the integral of f(x+-3)=(x-3)^2+3. Find the integral. Expand the integral \int\left(\left(x-3\right)^2+3\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\left(x-3\right)^2dx results in: \frac{\left(x-3\right)^{3}}{3}. The integral \int3dx results in: 3x.