Final Answer
$\frac{26}{15}$
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Step-by-step Solution
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1
Expand the integral $\int_{0}^{2}\left(x^4+2x^2-5\right)dx$ into $3$ integrals using the sum rule for integrals, to then solve each integral separately
$\int_{0}^{2} x^4dx+\int_{0}^{2}2x^2dx+\int_{0}^{2}-5dx$
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$\int_{0}^{2} x^4dx+\int_{0}^{2}2x^2dx+\int_{0}^{2}-5dx$
Learn how to solve definite integrals problems step by step online. Integrate the function x^4+2x^2+-5 from 0 to 2. Expand the integral \int_{0}^{2}\left(x^4+2x^2-5\right)dx into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{0}^{2} x^4dx results in: \frac{32}{5}. The integral \int_{0}^{2}2x^2dx results in: \frac{16}{3}. The integral \int_{0}^{2}-5dx results in: -10.
Final Answer
$\frac{26}{15}$
Exact Numeric Answer
$1.7333$