Final Answer
Step-by-step Solution
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Apply the product rule for differentiation: $(f\cdot g)'=f'\cdot g+f\cdot g'$, where $f=x^3+x^2$ and $g=x^2+8$
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$\frac{d}{dx}\left(x^3+x^2\right)\left(x^2+8\right)+\left(x^3+x^2\right)\frac{d}{dx}\left(x^2+8\right)$
Learn how to solve differential calculus problems step by step online. Simplify the expression f(x)=(x^3+x^2)(x^2+8). Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g', where f=x^3+x^2 and g=x^2+8. The derivative of a sum of two or more functions is the sum of the derivatives of each function. The derivative of a sum of two or more functions is the sum of the derivatives of each function. The derivative of the constant function (8) is equal to zero.