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$\int\left(\frac{2}{\sqrt{t}}+\frac{6}{\sqrt[3]{t^2}}\right)dt$
Learn how to solve integral calculus problems step by step online. Find the integral of f(t)=2/(t^1/2)+6/(t^2^1/3). Find the integral. Simplify the expression inside the integral. The integral \int\frac{2}{\sqrt{t}}dt results in: 4\sqrt{t}. The integral \int\frac{6}{\sqrt[3]{t^{2}}}dt results in: 18\sqrt[3]{t}.