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Prove that $\cos\left(3x\right)-\cos\left(x\right)+\sin\left(x\right)=0$ is not an identity

Step-by-step Solution

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Final answer to the problem

The equation is not an identity

Step-by-step Solution

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Apply the trigonometric identity: $\cos\left(a\right)-\cos\left(b\right)$$=-2\sin\left(\frac{a-b}{2}\right)\sin\left(\frac{a+b}{2}\right)$, where $a=3x$ and $b=x$

$-2\sin\left(\frac{3x-x}{2}\right)\sin\left(\frac{3x+x}{2}\right)+\sin\left(x\right)=0$

Learn how to solve differential calculus problems step by step online.

$-2\sin\left(\frac{3x-x}{2}\right)\sin\left(\frac{3x+x}{2}\right)+\sin\left(x\right)=0$

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Learn how to solve differential calculus problems step by step online. Prove that cos(3x)-cos(x)sin(x)=0 is not an identity. Apply the trigonometric identity: \cos\left(a\right)-\cos\left(b\right)=-2\sin\left(\frac{a-b}{2}\right)\sin\left(\frac{a+b}{2}\right), where a=3x and b=x. Combining like terms 3x and -x. Combining like terms 3x and x. Take \frac{2}{2} out of the fraction.

Final answer to the problem

The equation is not an identity

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Function Plot

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Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

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