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Find the roots of the polynomial $\frac{5\left(\frac{x^2+3x+5}{2x-1}\right)\left(2x^2-2x-13\right)}{4x^2-4x+1}$ by putting it in the form of an equation and then set it equal to zero
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$\frac{5\left(\frac{x^2+3x+5}{2x-1}\right)\left(2x^2-2x-13\right)}{4x^2-4x+1}=0$
Learn how to solve differential calculus problems step by step online. Find the roots of (5(x^2+3x+5)/(2x-1)(2x^2-2x+-13))/(4x^2-4x+1). Find the roots of the polynomial \frac{5\left(\frac{x^2+3x+5}{2x-1}\right)\left(2x^2-2x-13\right)}{4x^2-4x+1} by putting it in the form of an equation and then set it equal to zero. Multiplying the fraction by 5\left(2x^2-2x-13\right). Divide fractions \frac{\frac{5\left(x^2+3x+5\right)\left(2x^2-2x-13\right)}{2x-1}}{4x^2-4x+1} with Keep, Change, Flip: \frac{a}{b}\div c=\frac{a}{b}\div\frac{c}{1}=\frac{a}{b}\times\frac{1}{c}=\frac{a}{b\cdot c}. Multiply both sides of the equation by \left(2x-1\right)\left(4x^2-4x+1\right).