Final Answer
$\frac{94}{3}\sqrt{x^{3}}-\frac{141}{4}\sqrt[3]{x^{4}}-94\sqrt{x}+\frac{141}{2}\sqrt[3]{x^{2}}+C_0$
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Step-by-step Solution
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1
Find the integral
$\int\left(47\sqrt{x}-47\sqrt[3]{x}+\frac{-47}{\sqrt{x}}+\frac{47}{\sqrt[3]{x}}\right)dx$
Learn how to solve integrals of exponential functions problems step by step online.
$\int\left(47\sqrt{x}-47\sqrt[3]{x}+\frac{-47}{\sqrt{x}}+\frac{47}{\sqrt[3]{x}}\right)dx$
Learn how to solve integrals of exponential functions problems step by step online. Find the integral of 47x^1/2-47x^1/3-47/(x^1/2)47/(x^1/3). Find the integral. Expand the integral \int\left(47\sqrt{x}-47\sqrt[3]{x}+\frac{-47}{\sqrt{x}}+\frac{47}{\sqrt[3]{x}}\right)dx into 4 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int47\sqrt{x}dx results in: \frac{94}{3}\sqrt{x^{3}}. The integral \int-47\sqrt[3]{x}dx results in: -\frac{141}{4}\sqrt[3]{x^{4}}.
Final Answer
$\frac{94}{3}\sqrt{x^{3}}-\frac{141}{4}\sqrt[3]{x^{4}}-94\sqrt{x}+\frac{141}{2}\sqrt[3]{x^{2}}+C_0$