$-5+a=-4$
$\int_0^2\left(n^x\tan\left(n^x\right)\right)dx$
$\left(25-5\right)\left(5\right)$
$x^2-18x+80=0$
$\frac{x}{-2}-5\le\:-10$
$-\frac{3}{7}x^3x\left(\frac{2}{9}x^4-\frac{7}{6}x^3-\frac{1}{5}\right)$
$\frac{\left(4-3\right)+3\left(2+4-1\right)}{5\left(4\right)-6\left(3\right)}$
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