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Combine $x^2\left(x^2+2x+3\right)+\frac{-1}{x^2+2x+3}$ in a single fraction
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$\frac{3}{\frac{-1+x^2\left(x^2+2x+3\right)^2}{x^2+2x+3}}$
Learn how to solve one-variable linear inequalities problems step by step online. Simplify the expression 3/(x^2(x^2+2x+3)+-1/(x^2+2x+3)). Combine x^2\left(x^2+2x+3\right)+\frac{-1}{x^2+2x+3} in a single fraction. Divide fractions \frac{3}{\frac{-1+x^2\left(x^2+2x+3\right)^2}{x^2+2x+3}} with Keep, Change, Flip: a\div \frac{b}{c}=\frac{a}{1}\div\frac{b}{c}=\frac{a}{1}\times\frac{c}{b}=\frac{a\cdot c}{b}. Multiply the single term 3 by each term of the polynomial \left(x^2+2x+3\right). Multiply 2 times 3.