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Find the break even points of the polynomial $\frac{3}{x^2\left(x^2+2x+3\right)+\frac{-1}{x^2+2x+3}}$ by putting it in the form of an equation and then set it equal to zero
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$\frac{3}{x^2\left(x^2+2x+3\right)+\frac{-1}{x^2+2x+3}}=0$
Learn how to solve problems step by step online. Find the break even points of the expression 3/(x^2(x^2+2x+3)+-1/(x^2+2x+3)). Find the break even points of the polynomial \frac{3}{x^2\left(x^2+2x+3\right)+\frac{-1}{x^2+2x+3}} by putting it in the form of an equation and then set it equal to zero. Combine x^2\left(x^2+2x+3\right)+\frac{-1}{x^2+2x+3} in a single fraction. Divide fractions \frac{3}{\frac{-1+x^2\left(x^2+2x+3\right)^2}{x^2+2x+3}} with Keep, Change, Flip: a\div \frac{b}{c}=\frac{a}{1}\div\frac{b}{c}=\frac{a}{1}\times\frac{c}{b}=\frac{a\cdot c}{b}. Multiply both sides of the equation by -1+x^2\left(x^2+2x+3\right)^2.