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$\int\left(\frac{-8}{x}+\frac{-4}{x^2}+\frac{1}{x^3}+\frac{16}{2x-1}\right)dx$
Learn how to solve integrals of exponential functions problems step by step online. Find the integral of -8/x+-4/(x^2)1/(x^3)16/(2x-1). Find the integral. Expand the integral \int\left(\frac{-8}{x}+\frac{-4}{x^2}+\frac{1}{x^3}+\frac{16}{2x-1}\right)dx into 4 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{-8}{x}dx results in: -8\ln\left(x\right). The integral \int\frac{-4}{x^2}dx results in: \frac{4}{x}.