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Find the roots of the polynomial $\sqrt{x^2+12x+36}$ by putting it in the form of an equation and then set it equal to zero
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$\sqrt{x^2+12x+36}=0$
Learn how to solve equations problems step by step online. Find the roots of (x^2+12x+36)^1/2. Find the roots of the polynomial \sqrt{x^2+12x+36} by putting it in the form of an equation and then set it equal to zero. Removing the variable's exponent raising both sides of the equation to the power of 2. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=12 and c=36. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying.