Find the roots of $\sqrt{2x-88}=\sqrt{\frac{x}{6}}$

Learn how to solve differential calculus problems step by step online.

$\sqrt{2x-88}=\sqrt{\frac{x}{6}}$

Learn how to solve differential calculus problems step by step online. Find the roots of (2x-88)^1/2=(x/6)^1/2. Find the roots of the equation using the Quadratic Formula. The power of a quotient is equal to the quotient of the power of the numerator and denominator: \displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}. Simplify the fraction \frac{\sqrt{x}}{\sqrt{6}}. Removing the variable's exponent raising both sides of the equation to the power of 2.