Final Answer
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Apply the product rule for differentiation: $(f\cdot g)'=f'\cdot g+f\cdot g'$, where $f=\sin\left(x\right)$ and $g=\tan\left(x\right)\sec\left(x\right)$
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$\frac{d}{dx}\left(\sin\left(x\right)\right)\tan\left(x\right)\sec\left(x\right)+\sin\left(x\right)\frac{d}{dx}\left(\tan\left(x\right)\sec\left(x\right)\right)$
Learn how to solve differential calculus problems step by step online. Find the derivative of sin(x)tan(x)sec(x). Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g', where f=\sin\left(x\right) and g=\tan\left(x\right)\sec\left(x\right). Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g', where f=\tan\left(x\right) and g=\sec\left(x\right). The derivative of the sine of a function is equal to the cosine of that function times the derivative of that function, in other words, if {f(x) = \sin(x)}, then {f'(x) = \cos(x)\cdot D_x(x)}. Applying the trigonometric identity: \cos\left(\theta \right)\sec\left(\theta \right) = 1.