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Find the limit of $\frac{\ln\left(2+x\right)}{x+1}=1$ as $x$ approaches $-1$

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https://www.youtube.com/watch?v=cfOcOgr0E7U

Pre-Calculus - Condensing a logarithmic expression to one logarithm 2[3lnx - ln(x+1)-ln(x-1)]

https://www.youtube.com/watch?v=HS0--oEAT4I

Calculus - Take the log of both sides to find the derivative, y = (x(x^2 + 1)^2)/(sqrt(2x^2 - 1))

https://www.youtube.com/watch?v=7aF6Ck6ZRxw

Algebra 2 - Learn step by step how to simplify a complex fraction, (3/(x+1)) / (5/(x -1))

https://www.youtube.com/watch?v=uXVIkvfXzr8

Calculus Write the tangent line through a point of natural log equation, f(x)=3x^2 -ln(x) at (1, 3)

https://www.youtube.com/watch?v=FhFOCyTef04

Algebra 2 - Solve a system of equation when they are the same line, 3x - 2y = -15; x - (2/3)y = -5

https://www.youtube.com/watch?v=nrrINRUnk74

Function Plot

Plotting: $\frac{\ln\left(2+x\right)}{x+1}=1$

Main Topic: Limits by Direct Substitution

Find limits of functions at a specific point by directly plugging the value into the function.

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