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Evaluate the limit $\lim_{x\to-1}\left(\frac{\ln\left(2+x\right)}{x+1}=1\right)$ by replacing all occurrences of $x$ by $-1$
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$\frac{\ln\left(2-1\right)}{-1+1}=1$
Learn how to solve limits by direct substitution problems step by step online. Find the limit of ln(2+x)/(x+1)=1 as x approaches -1. Evaluate the limit \lim_{x\to-1}\left(\frac{\ln\left(2+x\right)}{x+1}=1\right) by replacing all occurrences of x by -1. Subtract the values 1 and -1. Subtract the values 2 and -1. Calculating the natural logarithm of 1.