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Removing the variable's exponent raising both sides of the equation to the power of $\frac{1}{3}$
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$x^2+4x=\sqrt[3]{y+y^2}$
Learn how to solve problems step by step online. Solve the equation (x^2+4x)^3=y+y^2. Removing the variable's exponent raising both sides of the equation to the power of \frac{1}{3}. Factor the polynomial x^2+4x. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value 4. Now, we can factor x^2+4x+4 as a squared binomial of the form \left(x+\frac{b}{2}\right)^2. The square root of 4 is .