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The cube of a binomial (sum) is equal to the cube of the first term, plus three times the square of the first by the second, plus three times the first by the square of the second, plus the cube of the second term. In other words: $(a+b)^3=a^3+3a^2b+3ab^2+b^3 = (x)^3+3(x)^2(3)+3(x)(3)^2+(3)^3 =$
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$x^3+3\cdot 3x^2+3\cdot 3^2x+3^3$
Learn how to solve sum rule of differentiation problems step by step online. Expand the expression (x+3)^3. The cube of a binomial (sum) is equal to the cube of the first term, plus three times the square of the first by the second, plus three times the first by the square of the second, plus the cube of the second term. In other words: (a+b)^3=a^3+3a^2b+3ab^2+b^3 = (x)^3+3(x)^2(3)+3(x)(3)^2+(3)^3 =. Multiply 3 times 3. Calculate the power 3^2. Multiply 3 times 9.