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Expand the expression $\left(x+3\right)^2$ using the square of a binomial: $(a+b)^2=a^2+2ab+b^2$
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$x^{2}+6x+9+\left(y-4\right)^2=21$
Learn how to solve equations problems step by step online. Solve the equation (x+3)^2+(y-4)^2=21. Expand the expression \left(x+3\right)^2 using the square of a binomial: (a+b)^2=a^2+2ab+b^2. We need to isolate the dependent variable , we can do that by simultaneously subtracting x^{2}+6x+9 from both sides of the equation. Simplify the product -(x^{2}+6x+9). Simplify the product -(6x+9).