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The cube of a binomial (sum) is equal to the cube of the first term, plus three times the square of the first by the second, plus three times the first by the square of the second, plus the cube of the second term. In other words: $(a+b)^3=a^3+3a^2b+3ab^2+b^3 = (p^3)^3+3(p^3)^2(4)+3(p^3)(4)^2+(4)^3 =$
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$\left(p^3-4\right)^3\left(p^{9}+12p^{6}+48p^3+64\right)$
Learn how to solve problems step by step online. Expand the expression (p^3-4)^3(p^3+4)^3. The cube of a binomial (sum) is equal to the cube of the first term, plus three times the square of the first by the second, plus three times the first by the square of the second, plus the cube of the second term. In other words: (a+b)^3=a^3+3a^2b+3ab^2+b^3 = (p^3)^3+3(p^3)^2(4)+3(p^3)(4)^2+(4)^3 =. The cube of a binomial (difference) is equal to the cube of the first term, minus three times the square of the first by the second, plus three times the first by the square of the second, minus the cube of the second term. In other words: (a-b)^3=a^3-3a^2b+3ab^2-b^3 = (p^3)^3+3(p^3)^2(-4)+3(p^3)(-4)^2+(-4)^3 =. We can multiply the polynomials \left(p^{9}-12p^{6}+48p^3-64\right)\left(p^{9}+12p^{6}+48p^3+64\right) by using the FOIL method. The acronym F O I L stands for multiplying the terms in each bracket in the following order: First by First (F\times F), Outer by Outer (O\times O), Inner by Inner (I\times I), Last by Last (L\times L). Then, combine the four terms in a sum.