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$\int\left(p^3-4\right)^3\left(p^3+4\right)^3dp$
Learn how to solve problems step by step online. Find the integral of (p^3-4)^3(p^3+4)^3. Find the integral. Rewrite the integrand \left(p^3-4\right)^3\left(p^3+4\right)^3 in expanded form. Expand the integral \int\left(p^{18}-48p^{12}+768p^{6}-4096\right)dp into 4 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int p^{18}dp results in: \frac{p^{19}}{19}.